Which one of the following is the correct set | vedclass

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(A, C) In $BeCl_2$,the central atom $Be$ has $2$ bond pairs and $0$ lone pairs,resulting in $sp$ hybridization and a linear shape. Thus,option $A$ is

Vedclass · Accepted Answer

$BCl_3, sp^2, 	ext{triangular planar}$

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(A, C) In $BeCl_2$,the central atom $Be$ has $2$ bond pairs and $0$ lone pairs,resulting in $sp$ hybridization and a linear shape. Thus,option $A$ is correct.In $BCl_3$,the central atom $B$ has $3$ bond pairs and $0$ lone pairs,resulting in $sp^2$ hybridization and a triangular planar shape. Thus,option $C$ is also correct.However,in standard multiple-choice questions of this type,both $A$ and $C$ are chemically accurate. Given the provided options,both $A$ and $C$ represent correct sets.

Which one of the following is the correct set with respect to molecule,hybridization and shape?

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